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6x^2+31x+18=-
We move all terms to the left:
6x^2+31x+18-(-)=0
We add all the numbers together, and all the variables
6x^2+31x+18-0=0
We add all the numbers together, and all the variables
6x^2+31x+18=0
a = 6; b = 31; c = +18;
Δ = b2-4ac
Δ = 312-4·6·18
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-23}{2*6}=\frac{-54}{12} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+23}{2*6}=\frac{-8}{12} =-2/3 $
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